Till KTH:s startsida Till KTH:s startsida

Nyhetsflöde

Logga in till din kurswebb

Du är inte inloggad på KTH så innehållet är inte anpassat efter dina val.

I Nyhetsflödet hittar du uppdateringar på sidor, schema och inlägg från lärare (när de även behöver nå tidigare registrerade studenter).

Januari 2015
Schemahandläggare skapade händelsen 14 november 2014
kommenterade 26 januari 2015

KD2430 Nuclear Exam

 
Mars 2012
Februari 2012
Lärare Mats Jansson skrev inlägget 27 februari 2012
 
Lärare Mats Jansson skrev inlägget 24 februari 2012
 
Lärare Mats Jansson skrev inlägget 22 februari 2012
 
Lärare Mats Jansson skrev inlägget 13 februari 2012
 
Januari 2012
under Allmänt

Mats Jansson skapade sidan 22 januari 2012

 
Mars 2011
Amir Shabanisefidan skrev inlägget 17 mars 2011
Lärare kommenterade 17 mars 2011

Problem 12: Who said you need to use everything that is given in the problem? I often give more data than is needed, it's a part of the problem to understand what to use and what not to use.

Problem 11: The exercises are taken from the 'old' Nuclear Chemistry course. The radiation chemistry questions are not included in this course (13 & 16 and half 11), so you don't have to bother about these. The thing you should be able to calculate is the dose rate.

(and to answer your question: First calculate the dose rate, then use the G-value given in problem 16 to obtain the H2O2-concentration. Plug the concentration into the the given equation and you will get the rate of oxidation. And no, oxidation rate is not the same as dose rate)

kommenterade 17 mars 2011

Thank you :)

 
Anna-Maria Eriksson skrev inlägget 17 mars 2011
Lärare kommenterade 17 mars 2011

I guess you are referring to one of the problems in the exercises. I realize that the expression that should have been used in the problem is 'the efficiency of the isotope exchange' or maybe even better, 'complete isotope exchange was achieved and the ratio between tritium and hydrogen at the acidic positions were 1.7:1'

When using radiotracers, complete isotope exchange is important (Lecture 5). Complete isotope exchange means that the ratio between non-radioactive element and radioactive isotope of the same element is the same everywhere in the system.

An isotope exchange efficiency would be a measure of how efficient the isotope exchange would be. That would mean that a part of the non-radioactive elemets would not be irreversibly excluded from interacting with the rest of the system or that the system isn't in equilibrium. In the example we are referring to this would mean that you don't have sufficient information to solve the problem (you don't know how the ratio tritium/'acidic hydrogen').

 
Helen Winberg Wang skrev inlägget 15 mars 2011
Lärare kommenterade 16 mars 2011

Which problems are you referring to?

 
Aatif Ur Rehman Akhtar skrev inlägget 15 mars 2011
Lärare kommenterade 15 mars 2011

ALL isotopes of the actinides are radioactive. However, Th-232, U-235 and U-238 have very long half-lives, so they still occur naturally (U-234 also occurs naturally, but that is only since it is in the decay chain of U-238).

Actinides are the group furthest down in the periodic table, including the elements Ac, Th, Pa, U, Np, Pu, Am, Cm, Bk, Cf, Es, Fm, Md, No and Lr, see lecture 6.

Lead is the heaviest element with stable isotopes. Sometimes Bi is considered to be the heaviest element with stable isotopes, since Bi-209 has a half-life of 2*10^19 years (="almost stable").

 
Susanna Liljegren Bergman skrev inlägget 8 mars 2011
 
Helen Winberg Wang skrev inlägget 7 mars 2011
Lärare kommenterade 7 mars 2011

Hi Helen,

Old exams can now be found at the home page http://www.kth.se/che/utbildning/kurswebbar/KD2430/VT11-1/2.28448/old-exams-in-nuclear-chemistry-1.80332

 
Sandra Dahlin skrev inlägget 4 mars 2011
Lärare kommenterade 4 mars 2011

Good. I'll prepare to show how to solve them.

Any other problem we shall take on the white board? Anyone?

 
Aatif Ur Rehman Akhtar skrev inlägget 2 mars 2011
 
Mats Jansson skrev inlägget 1 mars 2011
 
Mats Jansson skrev inlägget 1 mars 2011
 
Februari 2011
Aatif Ur Rehman Akhtar skrev inlägget 24 februari 2011
Lärare kommenterade 24 februari 2011

It's the abundance (the number 4.35 under "Cr50"). Natural Cr is 4.35% Cr50, 83.79% Cr52, 9.5% Cr53 and 2.36% Cr54.

kommenterade 24 februari 2011

ok thanks

 
Mats Jansson skrev inlägget 21 februari 2011
kommenterade 23 februari 2011

Hello,

At lec# 3 and slide # 14 in the exercise i could not understand the the both 2nd last steps like

N = 5.61*10^7 /3   = 1.87*10^7

why you devided by 3 the above moles ?

and lastly how you converted these moles to Tones ?

 

 

Lärare kommenterade 23 februari 2011

You have calculated the number of moles U-238 you have. You want to know how many moles U3O8 there is. One mole U3O8 has 3 moles U.

To convert from number of moles to weight you multiply by the molar mass.

kommenterade 23 februari 2011

thanks

 
Aatif Ur Rehman Akhtar skrev inlägget 23 februari 2011
 
Aatif Ur Rehman Akhtar skrev inlägget 22 februari 2011
 
Andreas Långvall skrev inlägget 19 februari 2011
Lärare kommenterade 21 februari 2011

kolla din mail

/mats

 
Fredrik Holmberg skrev inlägget 9 februari 2011
Lärare kommenterade 9 februari 2011

Yes, they will.

I'm at Lanzarote this week :D and I forgot to give Susanna the priveleges to make changes at the home page. This week's lectures will be up at latest Tuesday next week

 
Januari 2011
Sandra Dahlin skrev inlägget 26 januari 2011
Lärare kommenterade 26 januari 2011

The answers are now up on the home page, look under activities.

I have added some reading directions, see schedule in the right column of the starting page. I am not sure what material Susanna will use.

 
Sandra Dahlin skrev inlägget 18 januari 2011
 
Mats Jansson skrev inlägget 17 januari 2011